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A constant force of 12 N in the positive x direction acts on a 4.0-kg object as it moves from the origin to the point 6i-8j m. How much work is done by the given force during this displacement

Respuesta :

Answer:

Explanation:

Only force in the direction of motion does work

The force acts in the x direction

The x change of position was 6 m

W = Fd = 12(6) = 72 J

onyebuchinnaji

The work done by the given force during this displacement is determined as 120 J.

Work done on the object

The work done on the object is calculated as follows;

W = Fd

where;

  • d is the displacement of the object

d = √(6² + 8²)

d = 10 m

W = 12 x 10

W = 120 J

Learn  more about work done here: https://brainly.com/question/25573309

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