A car slows down at -5.00 m/s2 until it comes to a stop after traveling 15.0 m. How much time did it take to stop.

Answer:
2.45 seconds to the nearest hundredth.
Step-by-step explanation:
Acceleration a = -5, distance s = 15, time = ?.
Final velocity = v = 0.
We need to use the equations of motion under constant acceleration.
v^2 = u^2 + 2as where u is the initial velocity
0 = u^2 + 2*-5*15
u^2 = 150
so u = √150
Now we use v = u + at:
0 = √150 - 5t
t = √150/5
t = 2.45 seconds.