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The diagonal of a square is 8 cm.
What is the length of the side of this square?
Give your answer as an exact surd in its simplest form

Respuesta :

msm555

the length of the side of this square is [tex]4\sqrt{2} \:or \:5.65[/tex]cm

Answer:

Solutions Given:

let diagonal of square be AC: 8 cm

let each side be a.

As diagonal bisect square.

let it forms right angled triangle ABC .

Where diagonal AC is hypotenuse and a is their opposite side and base.

By using Pythagoras law

hypotenuse ²=opposite side²+base side²

8²=a²+a²

64=2a²

a²=[tex]\frac{64}{2}[/tex]

a²=32

doing square root on both side

[tex]\sqrt{a²}=\sqrt{32}[/tex]

a=±[tex]\sqrt{2*2*2*2*2}[/tex]

a=±2*2[tex]\sqrt{2}[/tex]

Since side of square is always positive so

a=4[tex]\sqrt{2}[/tex] or 5.65 cm

Ver imagen msm555
AadhPrit

Answer:

Given :

↠ The diagonal of a square is 8 cm.

To Find :

↠ The length of the side of square.

Using Formula :

Here is the formula to find the side of square if diagonal is given :

[tex]\implies{\sf{a = \sqrt{2} \dfrac{d}{2}}} [/tex]

Where :

  • ➺ a = side of square
  • ➺ d = diagonal of square

Solution :

Substituting the given value in the required formula :

[tex]{\dashrightarrow{\pmb{\sf{ \: a = \sqrt{2} \dfrac{d}{2}}}}}[/tex]

[tex]{\dashrightarrow{\sf{ \: a = \sqrt{2} \times \dfrac{8}{2}}}}[/tex]

[tex]{\dashrightarrow{\sf{ \: a = \sqrt{2} \times \cancel{\dfrac{8}{2}}}}}[/tex]

[tex]{\dashrightarrow{\sf{ \: a = \sqrt{2} \times 4}}}[/tex]

[tex]{\dashrightarrow{\sf{ \: a = 4\sqrt{2}}}}[/tex]

[tex]{\dashrightarrow{\sf{\underline{\underline{\red{ \: a = 5.65 \: cm}}}}}}[/tex]

Hence, the length of the side of square is 5.6 cm.

[tex]\underline{\rule{220pt}{3pt}}[/tex]

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