LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Finding missing sides- similar triangles Algebraic practice )

Answer:
x=7.85
Step-by-step explanation:
Give the triangles we know that:
[tex] \frac{cd}{fh} = \frac{de}{hg} = \frac{ce}{gf} [/tex]
Now we can substitute like usual
[tex] \frac{78}{fh} = \frac{117}{54} = \frac{ce}{5x + 1} [/tex]
Now we simplify the fraction in the middle
the middles fraction will =13/6
Therefore:
[tex] \frac{78}{fh} = \frac{13}{6} [/tex]
so 13fh=468
Therefore: fh=36
Now we can use the Pythagorean theorem
so
[tex]gf = \sqrt{ {54}^{2} - {36}^{2} } [/tex]
so gf=18√5
so 5x+1=18√5
so 5x=-1+18√5
so x=7.85
(I'm not too sure about this one tho)