The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.
The heat of vaporization has been the amount of heat required to vaporize 1 gram of liquid.
The heat required for the vaporization has been given as:
[tex]Q=m\Delta H_{vap}[/tex]
The heat of vaporization of water has been given as, [tex]\Delta H_{vap}=40.7\;\rm kJ/mol[/tex]
The mass of water sample has been, [tex]m=150\;\rm g[/tex]
Substituting the values for the heat energy absorbed, Q:
[tex]Q=150\;\times\;40.7\;\rm kJ\\ \textit Q=6,105\;kJ[/tex]
The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.
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