The expressions p(200 - 5p) and -5p2 + 200p define the same function. The function models the revenue a school would earn from selling raffle tickets at p dollars each. Can you find the following price without graphing? If the school charges $10, it will collect $1,500 in revenue. Find another price that would generate $1,500 in revenue

Respuesta :

The revenue function is the sum of the profit and the cost function

Another price that would generate $1,500 in revenue is $30

How to determine the other price

The revenue function is given as:

[tex]R(x) = 05p^2 + 200p[/tex]

When the revenue is 1500, the equation becomes

[tex]-5p^2 + 200p = 1500[/tex]

Collect like terms

[tex]-5p^2 + 200p - 1500 = 0[/tex]

Divide through by -5

[tex]p^2 - 40p +300 = 0[/tex]

Expand

[tex]p^2 - 30p - 10p +300 = 0[/tex]

Factorize

[tex]p(p - 30) - 10(p -30) = 0[/tex]

Factor out p - 30

[tex](p - 10) (p -30) = 0[/tex]

Solve for p

p = 10 or p = 30

Hence, another price that would generate $1,500 in revenue is $30

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