A)
1 mol MgBr2: 2 mol KBr
x mol MgBr2: 7 mol KBr
[tex] \frac{1}{2} = \frac{x}{7} [/tex]
[tex]x = \frac{7}{2} [/tex]
x＝3.5 mol
B)
1 mol MgBr2: 2 mol KBr
2 mol MgBr2: y mol KBr
[tex] \frac{1}{2} = \frac{2}{y} [/tex]
y＝4 mol
If we produce 7 moles of KBr, 3.5 moles of MgBr₂ we needed and if we produce 2 moles of MgBr₂, 4 moles of KBr needed.
Stoichiometry helps us use the balanced chemical equation to measures quantitative relationships and it is to calculate the amount of products and reactants that are given in a reaction.
According to the reaction
2K + MgBr₂ → 2KBr + Mg
To produce 2 moles of KBr, 1 mole of MgBr₂ is needed.
So, to produce 7 moles of KBr we need
7 moles KBr × [tex]\frac{1\ \text{mole}\ MgBr_2}{2\ \text{moles}\ KBr}[/tex]
= 3.5 moles of MgBr₂
Now,
To produce 2 moles of MgBr₂ we need
2 moles of MgBr₂ × [tex]\frac{2\ \text{moles}\ KBr}{1\ \text{mole}\ MgBr_2}[/tex]
= 4 moles of KBr
Thus, we can say that if we produce 7 moles of KBr, 3.5 moles of MgBr₂ we needed and if we produce 2 moles of MgBr₂, 4 moles of KBr needed.
Learn more about the Stoichiometry here: brainly.com/question/14935523
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