10. A compound has an empirical formula of CH, and a molecular mass of 6 points
210.3 amu. What is its molecular formula?*
CH2
C2H4
A
B.
CH10
CisH30
Oc.
OD.

Respuesta :

Answer:

Molecular formula = C₅H₁₀

Explanation:

From the question given above, the following data were obtained:

Empirical formula of compound => CH₂

Molar mass of compound = 70.1 amu

Molecular formula of compound =...?

The molecular formula of a compound is usually a multiple (n) of the empirical formula i.e

Molecular formula = [CH₂]ₙ

Thus, to obtain the molecular formula of the compound, we must first determine the value of n. The value of n can be obtained as follow:

[CH₂]ₙ = 70.1

[12 + (2×1)]n = 70.1

[12 + 2]n = 70.1

14n = 70.1

Divide both side by 14

n = 70.1 / 14

n = 5

Molecular formula = [CH₂]ₙ

Molecular formula = [CH₂]₅

Molecular formula = C₅H₁₀

Thus, the Molecular formula of the compound is C₅H₁₀.

Explanation:

HOPE THIS HELPS!

  • Empirical formula=CH
  • Molecular mass=210.3u

Empirical formula mass=

  • 12+1=13u

Now

[tex]\\ \rm\hookrightarrow n=\dfrac{Molecular\:mass}{Empirical\: formula}[/tex]

[tex]\\ \rm\hookrightarrow n=\dfrac{210.3}{13}[/tex]

[tex]\\ \rm\hookrightarrow n\approx 16[/tex]

Now

Molecular formula:-

  • n×Empirical formula
  • 16×CH
  • C_16H_16