The mass of magnesium chloride, MgCl₂ obtained from the reaction is 118.75 g
We'll begin by calculating the mass of Mg that reacted and the mass of MgCl₂ obtained from the balanced equation
Mg + 2HCI —> H₂ + MgCl₂
Molar mass of Mg = 24 g/mol
Mass of Mg from the balanced equation = 1 × 24 = 24 g
Molar mass of MgCl₂ = 24 + (35.5×2) = 95 g/mol
Mass of MgCl₂ from the balanced equation = 1 × 95 = 95 g
SUMMARY
From the balanced equation above,
24 g of Mg reacted to produce 95 g of MgCl₂.
From the balanced equation above,
24 g of Mg reacted to produce 95 g of MgCl₂.
Therefore,
30 g of Mg will react to produce = (30 × 95) / 24 = 118.75 g of MgCl₂.
Thus, 118.75 g of MgCl₂ were obtained from the reaction.
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