Respuesta :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex] \quad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

Let's assume the ratio constants in terms of x ~

that is ;

  • [tex] \sf2x[/tex]

and

  • [tex] \sf3x[/tex]

Now, according to question ~

[tex] \qquad \sf \dashrightarrow \: 2x + 3x = 30[/tex]

[tex]\qquad \sf \dashrightarrow \: 5x = 30[/tex]

[tex]\qquad \sf \dashrightarrow \: x = 30 \div 5[/tex]

[tex]\qquad \sf \dashrightarrow \: x = 6[/tex]

So, Derek gets :

[tex]\qquad \sf \dashrightarrow \: 2x = 2 \times 6 = £12[/tex]

And Eric gets :

[tex]\qquad \sf \dashrightarrow \: 3x = 3 \times 6 =£ 18[/tex]

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