meiwakumeru17 meiwakumeru17

23-01-2022
Mathematics

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The stable nuclide ²⁰⁶₈₂Pb is formed from ²³⁸₉₂U by a long series of α and β⁻ decays. Which of the following nuclides could NOT be involved in this decay series?

A) Th-234
B) U-239
C) Po-218
D) Bi-214
E) Rn-222

Respuesta :

perminuspatel perminuspatel

23-01-2022

Answer:

Rn-222

Step-by-step explanation:

this decay takes specified step therefore Rn-222is not a decaying process

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