Can anyone help me with this?? And show me how to do it please. Algebra 1 Exponential Function rate of change

Answer:
2
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a , b ] is
[tex]\frac{f(b)-f(a)}{b-a} [/tex]
Here [ a, b ] = [ - 1, 3 ] , then
f(b) = f(3) = 3² + 1 = 9 + 1 = 10
f(- 1) = (- 1)² + 1 = 1 + 1 = 2
average rate of change = [tex]\frac{10-2}{3-(-1)} [/tex] = [tex]\frac{8}{3+1} [/tex] = [tex]\frac{8}{4} [/tex] = 2