Respuesta :
[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1000\\ r=rate\to 1.25\%\to \frac{1.25}{100}\dotfill &0.0125\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1000[1+(0.0125)(2)]\implies A=1000(1.025)\implies A=1025[/tex]