Answer:
x = 12 when h(x) = 9
Solving:
[] The problem:
h(x) = [tex]\frac{1}{2} [/tex]x + 3
[] Plugging in our known values:
-> h(x) = 9, not h(9) where x = 9
9 = [tex]\frac{1}{2} [/tex]x + 3
[] Solving:
-> The problem
9 = [tex]\frac{1}{2} [/tex]x + 3
-> Subtract 3 from both sides
6 = [tex]\frac{1}{2} [/tex]x
-> Divide both sides by [tex]\frac{1}{2} [/tex]
12 = x or x = 12
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
