Answer:
Option C.
Step-by-step explanation:
[tex]\sf\:x^{2}-3x+7=0 [/tex]
Use the biquadratic formula.
[tex]\sf\:\x=\frac{-\left(-3\right)(+/-)\sqrt{\left(-3\right)^{2}-4\times 7}}{2} [/tex]
[tex]\sf\:x=\frac{-\left(-3\right)(+/-)\sqrt{9-4\times 7}}{2} [/tex]
[tex]\sf\:x=\frac{-\left(-3\right)(+/-)\sqrt{9-28}}{2} [/tex]
[tex]\sf\:x=\frac{-\left(-3\right)(+/-)\sqrt{-19}}{2} [/tex]
[tex]\sf\:x=\frac{3(+/-)\sqrt{19}}{2} [/tex]
Positive sign:
[tex]\boxed{\sf\:x=\frac{3+\sqrt{19}}{2}} [/tex]
Negative sign:
[tex]\boxed{\sf\:x=\frac{3-\sqrt{19}}{2}} [/tex]
Hope it helps ⚜
