What is an equation of the line that is perpendicular to y- 3 = -4(x+2) and
passes through the point (-5, 7)?
A. Y-7=-4(x+5) B. Y-7=1/4(x+5) C.y+7=-1/4(x-5). D. Y+7=4(x-5)

Respuesta :

Answer:

B

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

m is the slope and (a, b ) a point on the line

y - 3 = - 4(x + 2) ← is in point- slope form

with slope m = - 4

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular} [/tex] = - [tex]\frac{1}{m} [/tex] = - [tex]\frac{1}{-4} [/tex] = [tex]\frac{1}{4} [/tex]

Using (a, b ) = (- 5, 7 ) , then

y - 7 = [tex]\frac{1}{4} [/tex] (x - (- 5) ) , that is

y - 7 = [tex]\frac{1}{4} [/tex] (x + 5) → B