Answer:
9.03 × 10²² oxygen molecules.
Explanation:
We want to determine the number of oxygen molecules in 3.36 L of oxygen gas at STP.
Recall that at STP, for any gas, it has a volume of 22.4 liters per mole.
Additionally, recall that there are 6.02 × 10²³ substances in one mole of a substance.
With the given value, hence multiply:
[tex]\displaystyle \begin{aligned} 3.36\text{ L O$_2$} & \cdot \frac{1\text{ mol O$_2$}}{22.4\text{ L O$_2$}}\cdot \frac{6.02\times 10^{23}\text{ molecules O$_2$}}{1 \text{ mol O$_2$}} \\ \\ &= 9.03\times 10^{22} \text{ molecules O$_2$}\end{aligned} [/tex]
In conclusion, there are aobut 9.03 × 10²² oxygen molecules in 3.36 L of oxygen as at STP.
