Using the figure below, find the value of b, the value of b is mathematically given as
b=11.25
Generally, the equation for the comparison b/w the two triangles is mathematically given as
x^2+z^2=(a+b)^2...(1
Therefore
triABD
x^2=a^2+y^2
triADC
b^2+y^2=Z^2
Therefore, subbing into equ one
a^2+y^2+b^2+y^2=a(15)^2
a(15)^2=(a+b)^2
In conclusion, In Tri
tan60=y/a
√3*a=√a*√b
√3a=√b
Therefore
3a=b
a+b=15
a+3a=15
a=15/4
Therefore
b=15-15/4
b=11.25
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