Answer:
[tex]\boxed{\sf x = - 8}[/tex]
Step-by-step explanation:
Given equation :
[tex]16 = - 2x[/tex]
We need to find the value of x .
Solution :
[tex] \tt \implies16 = - 2x[/tex]
Change their sides :
[tex]\tt \implies - 2x = 16[/tex]
Divide both sides by -2 :-
[tex]\tt \implies \dfrac{ - 2x}{ - 2} = \dfrac{16}{ - 2} [/tex]
Cancel The LHS:
[tex]\tt \implies \cfrac{ \cancel{ - 2}x}{ \cancel{ - 2}} = \cfrac{16}{ 2} [/tex]
[tex]\tt \implies \cfrac{1x}{1} = \cfrac{16}{ - 2} [/tex]
[tex]\tt \implies{1x} = \cfrac{16}{ - 2} [/tex]
[tex]\tt \implies{x} = \cfrac{16}{ - 2} [/tex]
Cancel the RHS :
[tex]\tt \implies{x} = \cfrac{ \cancel{16} {}^{ 8} }{ \cancel{ {- 2}} ^{ - 1} } [/tex]
[tex]\tt \implies{x} = \cfrac{ 8}{ - 1} [/tex]
[tex]\tt \implies{x} = - 8[/tex]
We're done!
Hence, the value of x would be -8 .
[tex] \rule{225pt}{2pt}[/tex]
I hope this helps!
Let me know if you have any questions.
