The number of mole of sulphur, S needed for the reaction is 0.39 mole
From the question given above, the following data were obtained:
Mole = mass / molar mass
Mole of Al = 56.4 / 27
Mole of Al = 2.09 mole
16Al + 3S₈ —> 8Al₂S₃
From the balanced equation above,
16 moles of Al required with 3 moles of S.
Therefore,
2.09 moles of Al will require = (2.09 × 3) / 16 = 0.39 mole of S
Thus, 0.39 mole of Sulphur, S is required for the reaction.
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