The area of the figure changes by a factor of 9/16, when the figure is dilated by a factor of 3/4
When a shape is dilated, the size of the shape changes (i.e. it either compresses or enlarges)
The scale factor (k) is given as:
[tex]k = \frac 34[/tex]
The area of the shape will change by the square of the scale factor.
So, we have:
[tex]Area = k^2[/tex]
This gives
[tex]Area = (\frac 34)^2[/tex]
[tex]Area = \frac 9{16}[/tex]
Hence, the area of the figure changes by a factor of 9/16
Read more about dilation at:
https://brainly.com/question/8532602
