MARKING AS BRAINLIEST! LAST ATTEMPT! ( divisibility rules practice problems) how did I get 36 divisible by 2 , 3, 4, 6,9 ?

Answer:
Step-by-step explanation:
36 / 2 = 18
36 / 3 = 12
36 / 4 = 9
36 / 6 = 6
36 / 9 = 4
36 = 2 * 2 * 3 * 3 when divided into prime factors.
so you can have 0 1 2 twos and 0 1 2 threes. Obviously the zeros cannot be both for the 2 and 3 at the same time time.