A community organization sponsored a trip to a baseball game, offering bleacher seats for $20 and grandstand seats for $30. The organization sold $2600 worth of seating and 100 people attended the game. How many tickets did they sell for each type of seat?

Respuesta :

The number of bleacher seat is 40 and grandstand seats is 60

Data Given;

  • bleacher seat = $20
  • grandstand seat = $30
  • total amount generated = $2600
  • total number of people in attendance = 100

To solve this problem, we have to write a system of equation.

Let x represent the number of bleacher seat

let y represent the number of grandstand seat

[tex]x + y = 100... equation (i)\\20x + 30y = 2600... equation (ii)[/tex]

From equation (i)

x + y = 100

x = 100 - y ... equation (iii)

Put equation (iii) into equation (ii)

[tex]20x + 30y = 2600\\\\x = 100 - y\\20(100 - y) + 30y = 2600\\2000 - 20y + 30y = 2600\\2000 + 10y = 2600\\10y = 2600 - 2000\\10y = 600\\10y/10 = 600/10\\y = 60[/tex]

Since we know the value of y, let substitute it into equation i and solve for x

[tex]x + y = 100\\x = 100 - y\\x = 100 - 60\\x = 40[/tex]

From the calculations above, the number of bleacher seats is 40 and the grandstand seats is 60

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