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For the elementary process
N2O5(g)→N2(g)+NO3(g)
the activation energy (Ea) and overall ΔE are 154 and 136 kJ/mol, respectively.
What is the activation energy for the reverse reaction?

Respuesta :

Answer:

18 kJ/mol

Explanation:

Sorry, I could not place a picture so I put it in as a PDF.

Activation energy is required to initiate a chemical reaction along the reaction path. The activation energy for the reverse reaction will be 18 kJ/mol.

What is a reverse reaction?

A reverse reaction is the simultaneous conversion of the reactant into the products and the products back into the reactant.

Given,

Activation energy (Ea) = 154 kJ/mol

Overall Energy change = 136 kJ/mol

The activation energy of the reverse reaction is calculated as:

[tex]\rm Ea _{(rev)}= \rm Ea _{(fwd)} - \Delta Hrxn[/tex]

Substituting values in the above equation:

[tex]154 - 136 = 18 \;\rm kJ/mol[/tex]

Therefore, the activation energy of the reverse reaction is 18 kJ/mol.

Learn more about activation energy here:

https://brainly.com/question/14240275

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