Answer: 465
Work Shown:
[tex]S = \text{sum of the integers from 1 to n}\\\\
S = 1+2+3+\ldots+n\\\\
S = \frac{n(n+1)}{2}\\\\
S = \frac{30(30+1)}{2}\\\\
S = \frac{30(31)}{2}\\\\
S = \frac{930}{2}\\\\
S = 465\\\\
\text{Therefore, }1+2+3+\ldots+29+30 = 465[/tex]
