This problem is asking for the electronegativity differences and polarity for the bonds formed between and K and F, and N and O. At the end, the results are 3.16 and ionic, and 0.40 and covalent, respectively.
Types of bonds
In chemistry, chemical bonds are formed when elements either share or gain electrons. Once they form the bond, one can tell much of the properties of the resulting compound based on the type of bond formed.
In such a way, one can evidence de formation of covalent and ionic bonds, the former exhibited when the electronegativity difference is between 0 and about 1.6 and the former beyond 1.7.
Electronegativity
In chemistry, electronegativity is the tendency of an atom to attract electrons in a molecule, thus, we have the following for K, F, N and O as required: 0.82, 3.98, 3.04 and 3.44, respectively.
In such a way, one can calculate the difference electronegativity for the pairs KF and NO as shown below:
K-F =3.98 - 0.82 = 3.16
N-O = 3.44 - 3.04 = 0.40
Hence, the K-F bond turns out ionic whereas the N-O, covalent.
Learn more about electronegativity: https://brainly.com/question/2060520
