Answer:
y = 15° , ∠BAC = 78° , ∠ABC = 68° , ∠ACB = 34°
Step-by-step explanation:
we can find ∠ACB as it lies on a straight line,
∠ACB + 146 = 180°
∠ACB = 180° - 146°
∠ACB = 34°
We know that all sides of triangle equals to 180°
so,
∠BAC + ∠ABC + ∠ACB = 180°
5y + 3 + 4y + 8 + 34 = 180°
9y + 45° = 180°
9y = 135°
y = 15°
So know we can find angles =
∠BAC = 5y + 3 = 5(15) + 3 = 78°
∠ABC = 4y + 8 = 4(15) + 8 = 68°
we already know that ∠ACB = 34°
