answers and work for them please

Answer:
no solution
no solution
Step-by-step explanation:
To solve radical equations, you need to isolate the square root and square both sides. Then at the end, you must check solutions for extraneous solutions.
10.
[tex] \sqrt{5x - 10} + 6 = 4 [/tex]
[tex] \sqrt{5x - 10} = -2 [/tex]
A square root is always a non-negative number. Since the square root on the left equals -2, there is no real solution.
11.
[tex] \sqrt{2x^2 + 8x - 4} + 6 = 5 [/tex]
[tex] \sqrt{2x^2 + 8x - 4} = -1 [/tex]
A square root is always a non-negative number. Since the square root on the left equals -2, there is no real solution.