The graph of the system of inequalities can be seen at the end of the answer.
How to graph a system of inequalities?
Here we have the system:
x + 3y > -3
y < x + 1
First, we should write both in linear form, the second one is already on that form, so we need to transform the first one.
x + 3y > -3
3y > -x - 3
y > (1/3)*-x - 3/3
y > -x/3 - 1
Now we can write our system as:
y > -x/3 - 1
y < x + 1
To graph it, we first need to graph both of the lines, and because the symbols > and < are used, the points on the lines are not solutions, so we will use dashed lines.
- For y > -x/3 - 1, we shade above the line, because y is larger than the line.
- For y < x + 1, we shade below the line, because y is smaller than the line.
Then the graph will be the one that you can see below.
If you want to learn more about systems of inequalities, you can read:
https://brainly.com/question/9774970
