An equipotential surface that surrounds a point charge q has a potential of 549 V and an area of 2.11 m2. Determine q.

Respuesta :

The value of q is = 2.5x10⁻⁸C

Formula for electric potential at distance r

[tex]v = \frac{kq}{r}[/tex]

We have to find the radius of charge

[tex]A = 4pir^2[/tex]

[tex]r=\sqrt{\frac{A}{4pi} }[/tex]

A = 2.11

[tex]r= \sqrt{\frac{2.11m^2}{4*3.14} }[/tex]

r = 0.4096

The charge

[tex]V=\frac{kq}{r} \\\\q = \frac{vr}{k} \\\\q = \frac{549*0.4096}{8.99*10^9}[/tex]

q = 2.5x10⁻⁸C

What is the equipotential surface?

This is the surface that stands as the locus of points that have equal potentials.

Such a surface has the same electric potential at all of its points

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