Answer:
13.45 grams of NaCl will be produced
Explanation:
Given:
Mass of CuCl2 = 15 grams
Molar mass of CuCl2 = 134.5 g/mol
Mass of Na(NO3) = 20grams
Molar mass of Na(NO3) = 85 g/mol
To find:
Amount of Sodium chloride produced = ?
Solution:
No of moles of CuCl2 = 15/134.5 = 0.11 moles
No of moles of Na(NO3) = 20/85 = 0.23 moles,
1CuCl2 + 2Na(NO3) --> 1Cu(NO3)2 + 2NaCl
from the reaction, 1 mole of copper chloride reacts with 2 mole of NaNO3 to produce 2 moles of sodium chloride.
Hence, 0.11 mole of copper chloride will react with 0.23 mole of NaNO3 to produce 0.23 moles of sodium chloride.
Mass of 0.23 moles of NaCl = 0.23 × M.M of NaCl
(Molar mass of NaCl = 58.5)
Mass of 0.23 moles of NaCl = 0.23 × 58.5 = 13.45 grams
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