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[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

Let's solve ~

As the sky diver jumps from the plane it's initial velocity is 0

that is :

  • vi = 0

we have to find his speed after 1 second, so

  • t = 1

Now, let's plug the values in the formula to find vf ( final velocity )

[tex]\qquad \sf  \dashrightarrow \: vf = 10t + vi[/tex]

[tex]\qquad \sf  \dashrightarrow \: vf = 10(1) + 0[/tex]

[tex]\qquad \sf  \dashrightarrow \: vf = 10 \: \: m {s}^{ - 1} [/tex]

Statement:

A skydiver jumps from a plane.

To find out:

The velocity with which he would be travelling after 1 second.

Solution:

  • Initial velocity (vi) = 0 m/s [since he was at rest]
  • Time (t) = 1 s
  • Acceleration due to gravity (g) =[tex]10m {s}^{ - 2} [/tex]
  • Let the final velocity be vf.
  • We know the equation of motion for a freely falling body, i.e.,

[tex]vf = gt + vi[/tex]

  • Putting the values in the above equation, we get

[tex]vf = 10(1) + 0 \\ = > vf = 10 \: m {s}^{ - 1} [/tex]

Answer:

The skydiver will be travelling 10 m/s after 1 second.

Hope you could understand.

If you have any query, feel free to ask.

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