The moles of oxygen produced with 11 moles Al is 8. 25 moles. Thus, option A is correct.
The balanced chemical equation for the reaction is:
[tex]\rm 2\;Al_2O_3\;\rightarrow\;4\;Al\;+\;3\;O_2[/tex]
From the balanced chemical equation, the stoichiometric coefficient gives the idea about the moles of compound reacted and produced.
From the given balanced chemical equation, 2 moles of aluminum oxide produces 3 moles of oxygen and 4 moles of Aluminum.
The available moles of aluminum are 11 moles, the moles of oxygen produced is given by:
[tex]\rm 4\;mol\;Al=3\;mol\;O_2\\\\11\;mol\;Al=\dfrac{3}{4}\;\times\;11\;mol\;O_2\\\\ 11\;mol\;Al=8. 25\;mol\;O_2[/tex]
The moles of oxygen produced with 11 moles Al is 8. 25 moles. Thus, option A is correct.
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