A sample of ammonia reacts with oxygen as shown. 4NH3(g) 5O2(g) Right arrow. 4NO(g) 6H2O(g) What is the limiting reactant if 4. 0 g of NH3 react with 8. 0 g of oxygen? O2 because it produces only 0. 20 mol of NO. NH3 because it produces only 0. 20 mol of NO. O2 because it produces two times less NO than NH3. NH3 because it produces three times more NO than O2.

The limiting reactant in the chemical reaction is the reactant that is present in the lesser concentration with the another reactant and decides the product formation.

Limiting reactant in the reaction

The balanced equation for ammonia dissociation is:

[tex]\rm 4\;NH_3\;+\;5\;O_2\;\rightarrow\;4\;NO\;+\;6\;H_2O[/tex]

The moles of ammonia require is 4 moles to react with 5 moles of oxygen

The moles has been given as:

[tex]\rm Moles=\dfrac{Mass}{Molar\;mass}[/tex]

The available moles of ammonia in 4 gram is:

[tex]\rm Moles\;ammonia=\dfrac{4}{17}\\ Moles\;ammonia=0.23\;mol[/tex]

The available moles of oxygen in 8 grams is:

[tex]\rm Moles\;oxygen=\dfrac{8}{32}\\ Moles\;oxygen=0.25\;mol[/tex]

The moles of oxygen required for 0.23 moles of ammonia are:

[tex]\rm 4\;mol\;ammonia=5\;mol\;oxygen\\0,23\;mol\;ammonia=\dfrac{5}{4}\;\times\;0.23\;mol\;oxygen\\ 0.23\;mol\;ammonia=0.28\;mol\;oxygen[/tex]

The required moles of oxygen is 0.28 mol, however the available moles of oxygen are 0.25 mol. Thus, oxygen is the limiting reagent.

Thus, option A is correct.

Learn more about moles produced, here:

https://brainly.com/question/14225536