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You found an old push-button phone in your room, but unfortunately some of the buttons are broken and can't be pushed anymore. To test the phone, you decided to try typing a message to your friend. Your task is to find which words of this message will be possible to type using the broken keypad. You are given an array of integers digits representing the set of phone buttons which are still working. You are also given an array of strings words containing the words you'd like to type in your message. Return an array of booleans, where the ith element is true if it is possible to type the ith word, and false otherwise.

Respuesta :

okpalawalter8

We have that the print code is mathematically given as

The

  // print

  for(int i=0; i<SIZE;i++){

      if(possibles[i])cout<<words[i]<<" *CAN* be texted\n";

      else                cout<<words[i]<<" *CANNOT* be texted\n";

  }

  return 0;

}

Code

Generally the Code is

// to accurately convert from the letter to the key pad digit

int getLetterDigit(char letter){

  switch(letter){

      case 'a':case 'b': case 'c':return 2;

      case 'd':case 'e': case 'f':return 3;

      case 'g':case 'h': case 'i':return 4;

      case 'j':case 'k': case 'l':return 5;

      case 'm':case 'n': case 'o':return 6;

      case 'p':case 'q': case 'r': case 's': return 7;

      case 't':case 'u': case 'v':return 8;

      case 'w':case 'x': case 'y': case 'z': return 9;

  }

  return 0;

}

//  the digit is in the array - broken

bool isDigitInArray(int digit, int broken[], int size){

  for(int i=0; i<size; i++){

      if(broken[i]==digit)return true;

  }

  return false;

}

bool canBeTexted(string word, int broken[], int arraySize){

 

  char letter; int digit;

  for(int i=0; i<word.length(); i++){

      letter = tolower(word.at(i));

      digit = getLetterDigit(letter);

      if(isDigitInArray(digit,broken,arraySize))

{

          return false;

      }

  }

  return true;

}

int main(){

const int SIZE = 11; //the size of the message there are 11 words

  // the array

  string words[SIZE] ={"Hi","John","I","am","sick","I","can\'t","come","to","play","today"};

  bool possibles[SIZE];

  int broken[] = {5,1}

  for(int i=0; i<SIZE;i++){

      possibles[i] = canBeTexted(words[i],broken,2);

  }

  // print the words that can be messaged and the one that cannot be

  for(int i=0; i<SIZE;i++){

      if(possibles[i])cout<<words[i]<<" *CAN* be texted\n";

      else                cout<<words[i]<<" *CANNOT* be texted\n";

  }

  return 0;

}

For more information on code  visit

https://brainly.com/question/950632

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