Respuesta :
The mass of hydrogen requires to completely react with 8. 75 g of oxygen is 1 grams.
The balanced chemical equation for the reaction is:
[tex]\rm O_2\;+\;2\;H_2\;\rightarrow\;2\;H_2O[/tex]
Computation for mass of hydrogen required
The moles of substance required and formed in the reaction is given by the stoichiometric coefficient of the balanced chemical equation.
The equation gives, for the complete reaction of 1 moles of oxygen requires, 2 moles of hydrogen.
The mass of oxygen with moles is given as:
[tex]\rm Mass=Moles\;\times\;Molar\;mass[/tex]
The mass of hydrogen required for 8. 75 g oxygen is:
[tex]\rm 1\;\times\;32\;g\;O_2=2\;\times\;2\;g\;H_2\\\\8. 75\;g\;O_2=\dfrac{2\;\times\;2\;H_2}{1\;\times\;32\;O_2}\;\times\;8. 75\;g\;H_2 \\\\8. 75\;g\;O_2=1\;g\;H_2[/tex]
The mass of hydrogen requires to completely react with 8. 75 g of oxygen is 1 grams.
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