Jtyson14
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For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 28 N acts on a certain object, the
acceleration of the object is 4 m/s. If the force is changed to 49 N, what will be the acceleration of the object?

Respuesta :

mhanifa

Answer:

  • 7 m/s

Step-by-step explanation:

Direct variation equation:

  • y = kx, where y- force, x- acceleration, k - coefficient

We have:

  • y = 28 and x = 4

Find the value of k:

  • 28 = 4k
  • k = 28/4
  • k = 7

Our equation is:

  • y = 7x

Now, find the value of x when y = 49:

  • 49 = 7x
  • x = 49/7
  • x = 7

[tex]\\ \tt\longmapsto Force\propto Acceleration [/tex]

  • F_1=28N
  • a_1=4m/s^2
  • F_2=49N
  • a_2=?

[tex]\\ \tt\longmapsto F_1a_2=F_2a_1[/tex]

[tex]\\ \tt\longmapsto 28a_2=4(49)[/tex]

[tex]\\ \tt\longmapsto 28a_2=196[/tex]

[tex]\\ \tt\longmapsto a_2=7m/s^2[/tex]