50/50
two people who have never been there before
chances are higher if one of them checks reviews
The probability they will choose a restaurant that only one of them has
been to before is; 0.6
We are told that both Amna and Mani are choosing a restaurant for lunch.
Now, decide to choose a restaurant at random from the first 10
search results in the neighborhood.
Each of them have been to 3 restaurants out of the 10. The 3 each have visited differ from each other.
Thus;
Probability that Amna will choose a restaurant visited before = 3/10
Probability that Mani will choose a restaurant visited before = 3/10
probability they will choose a restaurant that only one of them has
been to before = 3/10 + 3/10 = 6/10 = 0.6
Read more about Probability Selection at; https://brainly.com/question/251701
