The energy of the photon with a frequency of 3.6×10¹⁵ Hz is 2.4×10¯¹⁸ J
Energy is defined as the ability to do work.
The energy of a photon is related to it's frequency according to the following equation:
Energy (E) = Planck's constant (h) × frequency (f)
E = hf
With the above formula, we can obtain the energy of the photon.
E = hf
E = 6.63×10¯³⁴ × 3.6×10¹⁵
E = 2.4×10¯¹⁸ J
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The energy of the photon is 2.4 × 10⁻¹⁸ J. The correct option is the last option 2. 4 × 10–18 J.
From the question,
We are to calculate the energy of a photon with a frequency of 3.6 × 10¹⁵ Hz
The energy of a photon can be calculated by using the formula,
[tex]E = h\nu[/tex]
Where [tex]E[/tex] is the Energy
[tex]h[/tex] is the Planck's constant
and [tex]\nu[/tex] is the frequency
From the given information
[tex]h = 6.63 \times 10^{-34} \ J.s[/tex]
[tex]\nu = 3.6 \times 10^{15} \ Hz[/tex]
Therefore,
[tex]E = 6.63 \times 10^{-34} \times 3.6 \times 10^{15}[/tex]
[tex]E = 2.3868 \times 10^{-18} \ J[/tex]
[tex]E \approx 2.4 \times 10^{-18} \ J[/tex]
Hence, the energy of the photon is 2.4 × 10⁻¹⁸ J. The correct option is the last option 2. 4 × 10–18 J.
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