The joining of each three, two penultimate points on the circumference
of the circle, without intersection gives an equilateral triangle.
Response:
- The segments that Zahid needs to draw are; DF, BF, and BD
How can the equilateral triangle be constructed from the given construction on the circle?
The assumption can be taken that, the steps used to construct the
equilateral triangle inscribed in the circle by marking along the
circumference of the circle at 6 points using the radial length.
Therefore;
The lengths of the chords formed by joining a marked points to another point such that one marked point is between the two are equal.
Which gives;
The length of the chord, DF = The length of the chord, BF = The length of the chord, BD
Given that the joining DF, BF and BD forms a triangle, and DF = BF = BD, we have;
ΔBDF is an equilateral triangle, therefore;
To finish his construction, Zahid needs to draw segments DF;
Learn more about geometric construction here:
https://brainly.com/question/13160630