The number of grams of calcium metal will be deposited in the electrolysis of molten Cabr₂ is; 224 g
Total time; t = 10 hours = 36000 seconds
Charge supplied; Q = i * t
Q = 30.0 A × 36000 s
Q = 1080000 C
Number of moles of electrons = Charge supplied/Faraday's constant
Number of moles of electrons = 1080000 C/96500 C
Number of moles of electrons = 11.2 mol
The ionic equation for Ca deposited is;
Ca²⁺ + 2e⁻ → Ca
Thus;
2 mol of electron gives 1 mol of Ca²⁺
Thus;
112. 2 mols of electron will give; 11.2/2 mol of Ca²⁺ = 5.6 mol of Ca²⁺
Molar mass of Ca = 40
Thus; Mass of Calcium deposited = 5.6 * 40 = 224 g
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