The wire 2 has the most charge flowing in it at the given time interval.
The total charge flowing in each wire is calculated using the following equation;
Q = It
where;
The charge flowing in wire 1 is calculated as follows;
Q = 1 x 60 = 60 C
The charge flowing in wire 2 is calculated as follows;
Q = 2 x 45 = 90 C
The charge flowing in wire 3 is calculated as follows;
Q = 3 x 10 = 30 C
Thus, the wire 2 has the most charge flowing in it at the given time interval.
The complete question is below
The current across three identical current carrying wires is measured during a certain time interval. The reading is reported in the table
Current (A) Time Interval (S)
Wire 1 1 60
Wire 2 2 45
Wire 3 3 10
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