Respuesta :
The molality of chloride ions is 4.63kg/L
Data;
- Mole Fraction = 0.0400
- Molality of Chloride ions = ?
Molality of Chloride ions
Mole Fraction of MgCl2 = 0.04
The sum of mole fraction = 1
Mole fraction of water = 1 - 0.04 = 0.96
since the total number of moles = 1
Number of moles of MgCl2 = mole fraction * total number of moles
Number of moles of MgCl2
[tex]0.04 * 1 = 0.04 moles[/tex]
Number of moles of water =
[tex]0.96 * 1 = 0.96 moles[/tex]
1 moles of MgCl2 = 2 moles of Chloride ions
Number of moles of chloride ions
[tex]2 * 0.04 = 0.08 moles[/tex]
Number of moles of water = 0.96moles
mass of water = molecular weight * number of moles
mass of water =
[tex]18 * 0.96 = 17.28g[/tex]
let's convert this to kilogram
[tex]1000g = 1kg\\17.28g = x\\x = 0.01728kg\\[/tex]
The molality of the ions in the solution is
[tex]M = \frac{mass of solute}{volume of solution} \\M = \frac{0.08}{0.01728} =4.63 kg/L[/tex]
The molality of chloride ions is 4.63kg/L
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