Help pleaseeee I’m in need

* Which value can you use for n to show that the

first step in a proof by mathematical induction of

"For all the positive integers n

1^2+2^2+...+n^2?

n(n+1) (2n+1)" /6 is true?

A-n=1/4

B- n=1

C- n=3.26

D- n=-10.1

"For all the positive integers n" is a qualifying statement. The number used has to be positive and also must be an integer. Integers are whole numbers and their opposites, so basically no fractions and no decimals. Answer A is a fraction and C is a decimal and D is negative and a decimal. So they don't work for this problem.

Answer Link

Help pleaseeee I’m in need * Which value can you use for n to show that the first step in a proof by mathematical induction of "For all the positive integers n 1^2+2^2+...+n^2? n(n+1) (2n+1)" /6 is true? A-n=1/4 B- n=1 C- n=3.26 D- n=-10.1

Respuesta :

Otras preguntas

Help pleaseeee I’m in need

* Which value can you use for n to show that the

first step in a proof by mathematical induction of

"For all the positive integers n

1^2+2^2+...+n^2?

n(n+1) (2n+1)" /6 is true?

A-n=1/4

B- n=1

C- n=3.26

D- n=-10.1