Please help! THIS IS DUE IN A HOUR!
I will give you brainliest if you help me! I’ll vote and heart it.

1. Calculate the energy of an X-ray photon if the wavelength is 5.00x10^-10m?

2. (use picture) Determine the energy related to an electron occupying the ground state a Hydrogen atom given its bright-line spectrum below (the one to the left with least frequency):

3. A laser used to detach retinas produces radiation with a frequency of 4.6x10^14 Hz. What is the wavelength of this light?

Please help THIS IS DUE IN A HOUR I will give you brainliest if you help me Ill vote and heart it 1 Calculate the energy of an Xray photon if the wavelength is class=

Respuesta :

[tex]\bold{\huge{\pink{\underline{ Answer }}}}[/tex]

Concept Used :-

Here, we will use the concept of planks quantum theory .

According to planks quantum theory :-

  • The radiant energy is emitted discontinuously in the form of small packets of energy called quanta
  • In case of lights, It is called photons
  • The amount of energy with each quantum of radiation is directly proportional to the frequency of light
  • That is,
  • E = hv or E = hc/ λ
  • The total amount of energy emitted or a absorbed will be whole number multiple of quantum
  • That is,
  • E = nhv or nhc/λ

Answer 1 :-

Here,

We have to calculate the energy of an X photon

  • The wavelength is 5.00 × 10^-10
  • The value of planks constant h is 6.626 × 10^-34 .

According to the planks quantum theory of radiation :-

[tex]\bold{\pink{ E = hv }}[/tex]

[tex]\sf{ E = h}{\sf{\times{\dfrac{c}{λ}}}}[/tex]

  • The value of c is 3 × 10^8

Subsitute the required values,

[tex]\sf{ E = 6.626 × 10^{-34} }{\sf{\times{\dfrac{3 × 10^{8}}{5 × 10^{-10}}}}}[/tex]

[tex]\sf{ E = }{\sf{\dfrac{19.87× 10^{-26}}{5 × 10^{-10}}}}[/tex]

[tex]\sf{ E = 3.974 × 10^{-36}}[/tex]

Hence, The energy of an X ray photon is 3.974 × 10^-36

Answer 2 :-

We have ,

  • Frequency = 4.57 × 10^14 Hz
  • Planks constant = 6.626 × 10^-34

According to the planks quantum theory,

[tex]\bold{\pink{ E = hv }}[/tex]

Subsitute the required values,

[tex]\sf{ E = 6.626 × 10^{-34}× 4.57 × 10^{14}}[/tex]

[tex]\sf{ E = 30.28 × 10^{- 20}}[/tex]

[tex]\sf{ E = 3.028 × 10^{ - 19}}[/tex]

Hence, The energy related to an electron occupying the ground state of hydrogen atoms is 3.028 × 10^-19

Answer 3 :-

We have ,

  • Frequency = 4.6 × 10^14 Hz

We know that,

[tex]\bold{\pink{ v = }}{\bold{\pink{\dfrac{ c }{λ}}}}[/tex]

[tex]\sf{ λ = }{\sf{\dfrac{ c }{v}}}[/tex]

Subsitute the required values,

[tex]\sf{ λ = }{\sf{\dfrac{ 3 × 10^{8} }{4.6 × 10^{-14}}}}[/tex]

[tex]\sf{ λ = 0.65 × 10^{22}}[/tex]

Hence, The of this light is 0.65 × 10^22 .

[ Note :- Kindly refer answer in the app]