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Answer:
I'm certainly late, but it took me a while to figure this one out so I want to leave an answer.
A=-5 B=2 C=19 D=-2
Step-by-step explanation:
I looked back at the video and actually tried to pay attention and the way to figure these problems out is set up all of the degrees of x in an equation. So, take all of the coefficients that are attached to an x^3, and set them up equal to each other. This makes -5=A, which is the first answer. Repeat for x^2 and you have B=2. For x, it becomes 9=2A+C. A is equal to -5 (from the x^3), so you can substitute and get c=19. Repeat for the x^0 term (the constants), and you get 2=2B+D. Plug in the value for B, 2, and get 2=4+D, which then becomes D=-2. That's how you get the answer and I hope this helps somebody.
The values are A=-5, B=2, C=19 and D=-2
What is partial fraction?
Partial fractions are the fractions used for the decomposition of a rational expression. When an algebraic expression is split into a sum of two or more rational expressions, then each part is called a partial fraction. Hence, basically, it is the reverse of the addition of rational expressions.
Given:(-5x³+2x²+9x+2) / x²+2 =(Ax + B)/x²+2 + (Cx + d)/x²+2 .......(1)
First, we have to perform the long division as follows
The long division gives
(-5x³+2x²+9x+2 )/ x²+2= ( -5x+2)+ (19x-2)/ x²+2
Now, we have to find the partial fraction for (19x-2)/ x²+2
But, as denominator cannot be factored, So no partial fraction can be calculated.
Thus, (-5x³+2x²+9x+2 )/ x²+2= ( -5x+2)+ (19x-2)/ x²+2
Comparing it with equation (1), we get
Hence, A=-5, B=2, C=19 and D= -2
Learn more about partial fraction here:
https://brainly.com/question/23125414
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