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2 KCIO3 → 2 KCl + 3 02
If 195 grams of Potassium Chlorate (FM = 122.55 grams) decomposes, how much Oxygen (FM =
32.00 grams) will be produced in this reaction?

Respuesta :

Oseni

The amount of oxygen that would be produced will be 76.38 grams

Stoichiometric calculation

From the equation of the reaction, the mole ratio of KCIO3 to O2 is 2:3. That is, for every one mole of KCIO3 that decomposes, 1.5 moles of oxygen is produced.

Mole of 195 grams KCIO3 = 195/122.55

                                            = 1.59 moles

Equivalent mole of O2 = 1.59 x 3/2

                                     = 2.39 moles

Mass of 2.39 moles oxygen = 2.39 x 32

                                               = 76.38 grams

More on stoichiometric calculations can be found here: https://brainly.com/question/8062886

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