Answer:
[tex]2x^3 + 5x^2 - x - 6[/tex]
Step-by-step explanation:
[NOTE]
I am assuming x2 is [tex]x^2[/tex], if I am wrong about that then please notify me in the comments
[END NOTE]
The parenthesis are implications that we multiply the numbers within them.
Therefore, multiply.
(2x)(x2)
[tex]2x^3[/tex]
(2x)(x)
[tex]2x^2[/tex]
[tex]2x^3 + 2x^2[/tex]
(2x)(-2)
-4x
[tex]2x^3+2x^2-4x[/tex]
(3)(x2)
[tex]3x^2[/tex]
[tex]2x^3+2x^2-4x+3x^2[/tex]
(3)(x)
3x
[tex]2x^3+2x^2-4x+3x^2+3x[/tex]
(3)(-2)
-6
[tex]2x^3+2x^2-4x+3x^2+3x-6[/tex]
Now combine like terms, meaning the numbers with the same endings, you cannot add a number with different exponents and adding numbers with and without a variable.
[tex]2x^3 + 5x^2 - x - 6[/tex]