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2. The electrostatic force of attraction between two small spheres that are 1.0 m apart is F. If the distance between the spheres is decreased to 0.5 m, the electrostatic force will then be

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Eduard22sly

The electrostatic force between the two spheres when their distance is decrease to 0.5 m will be 4F

Data obtained from the question

  • Initial distance apart (r₁) = 1 m
  • Initial force (F₁) = F
  • Final distance apart (r₂) = 0.5 m
  • Final force (F₂) =?

How to determine the final force

From Coulomb's law,

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Kq₁q₂ = constant

F₁r₁² = F₂r₂²

With the above formula, we can obtain the final force as follow:

F₁r₁² = F₂r₂²

F × 1² = F₂ × 0.5²

F = F₂ × 0.25

Divide both side by 0.25

F₂ = F / 0.25

F₂ = 4F

Thus, we can conclude that the final force will increase by a factor of 4

Learn more about Coulomb's law:

https://brainly.com/question/506926

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