Using complementary events, considering a [tex]\frac{1}{4}[/tex] probability of drawing a red marble, the probability of not drawing a red marble is of [tex]\frac{3}{4}[/tex].
They are mutually exclusive events which have the sum of their probabilities as 1.
In this problem, we consider that there is a [tex]\frac{1}{4}[/tex] probability of drawing a red marble, and since drawing a red marble and drawing a non-red marble are complementary events, we have that:
[tex]\frac{1}{4} + p = 1[/tex]
[tex]p = \frac{3}{4}[/tex]
The probability of not drawing a red marble is of [tex]\frac{3}{4}[/tex].
More can be learned about complementary events at https://brainly.com/question/9752956